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Name
Reg No

APJ ABDUL KALAM TECHNOLOGICAL UNIVERSITY
07 THRISSUR CLUSTER
FIRSTSEMESTER M.TECH. DEGREE EXAMINATION DEC 2017
Chemical Engineering Department
(Process Control)
07CH 6103 Process Dynamics and Control I
Time:3 hours Max.Marks: 60
Answer all six questions. Part of each question is compulsory.
Answer either part or part of eachquestion
(Semi logarithmic and ordinary graph sheets shall be provided.)
Q.no. Module 1 Marks
1a Explain Bode and Nyquist stability criterion. 4
Answer b or c
b A feedback control system has a characteristic equation S2+ 2S5+
9S4+16S3+24S2+32S+16. Determine the number of poles
1. On the right half of the S-plane.
2. On imaginary axis.
3. On the left half of S-plane.
5
c Derive the frequency response of PI, PD, PID controllers. 5
Q.no. Module 2 Marks
2a Write down the describing function for various nonlinearities in a process 4
Answer b or c
b Explain the characteristics of nonlinear systems. 5
c Draw the phase trajectory of the system Comment the stability of the
system
5
Q.no. Module 3 Marks
3a Explain with a neat sketch the characteristics of a control valve. 4
Answer b or c
b Draw and explain pneumatic controllers. 5
c Describe valve sizing and valve positioners. 5
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Q.no. Module 4 Marks
4a Explain the working of cascade control with a neat sketch and block diagram.
List out the advantages of cascade control over the feedback control system.
4
Answer b or c
b Explain various error performance indexes used as performance criteria of
controllers.
5
c Problem-tuning 5
Q.no. Module 5 Marks
5a What is adaptive control? Discuss its applications in chemical process control. 5
Answer b or c
b Explain with the help of block diagram
1. Sampling
2. Zero order hold
3. Impulse modulated function
7
c Elucidate with the help of block diagram
1. Self tuning regulator
2. Dead time compensator
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Q.no. Module 6 Marks
6a Invert


5
Answer b or c
b Find the closed loop sampled data response of the following control systems.
Where ZOH



1


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c Find the stability of the sampled data control systems described by the
characteristic equation z3+3z2-2.75z+0.75=0.
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